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x^2+20x-7.5=0
a = 1; b = 20; c = -7.5;
Δ = b2-4ac
Δ = 202-4·1·(-7.5)
Δ = 430
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-\sqrt{430}}{2*1}=\frac{-20-\sqrt{430}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+\sqrt{430}}{2*1}=\frac{-20+\sqrt{430}}{2} $
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